RRB Technician Grade III 2024-25 – 23 December 2024 Shift 3 · Solutions, solubility and concentration
Q101. A solution contains 20 g of common salt in 280 g of water. What is the concentration in terms of mass by mass percentage of the solution?
- (a) 66.6%
- (b) 0.66%
- (c) 6.66%
- (d) 11.1%
Answer & solution
Answer: (c) 6.66%
Correct Answer: Option 3 — 6.66%
The mass by mass percentage of a solution is
Mass % = (Mass of solute / Mass of solution) × 100, where Mass of solution = Mass of solute + Mass of solvent.
⚗️ The Calculation
• Mass of solute (common salt) = 20 g; mass of solvent (water) = 280 g.
• Mass of solution = 20 + 280 = 300 g.
• Mass % = (20/300) × 100 = 2000/300 = 6.66%.
So the solution is 6.66% (by mass) common salt. Note that the solvent mass alone is never used in the denominator — the mass of the whole solution must be taken.
❌ Why the other options are incorrect
✗ 66.6% — this is ten times the right value; it comes from a decimal-point slip while dividing 2000 by 300.
✗ 0.66% — again a decimal error, ten times too small; here the ×100 has effectively been applied wrongly.
✗ 11.1% — this is (20/180) × 100 or a similar wrong denominator; the commonest trap is dividing by 280 g of water instead of the 300 g of solution — that would give 7.14%, and using an even smaller denominator gives 11.1%.
📌 SSC & Railway Exam Facts
• Mass % = (mass of solute / mass of solution) × 100; solution = solute + solvent.
• Volume % = (volume of solute / volume of solution) × 100.
• Common salt = sodium chloride = NaCl; obtained from sea water and rock salt.
• Saturated solution: no more solute dissolves at that temperature; solubility usually rises with temperature.
• Water is the universal solvent; a solution of a metal in a metal is an alloy.
The mass by mass percentage of a solution is
Mass % = (Mass of solute / Mass of solution) × 100, where Mass of solution = Mass of solute + Mass of solvent.
⚗️ The Calculation
• Mass of solute (common salt) = 20 g; mass of solvent (water) = 280 g.
• Mass of solution = 20 + 280 = 300 g.
• Mass % = (20/300) × 100 = 2000/300 = 6.66%.
So the solution is 6.66% (by mass) common salt. Note that the solvent mass alone is never used in the denominator — the mass of the whole solution must be taken.
❌ Why the other options are incorrect
✗ 66.6% — this is ten times the right value; it comes from a decimal-point slip while dividing 2000 by 300.
✗ 0.66% — again a decimal error, ten times too small; here the ×100 has effectively been applied wrongly.
✗ 11.1% — this is (20/180) × 100 or a similar wrong denominator; the commonest trap is dividing by 280 g of water instead of the 300 g of solution — that would give 7.14%, and using an even smaller denominator gives 11.1%.
📌 SSC & Railway Exam Facts
• Mass % = (mass of solute / mass of solution) × 100; solution = solute + solvent.
• Volume % = (volume of solute / volume of solution) × 100.
• Common salt = sodium chloride = NaCl; obtained from sea water and rock salt.
• Saturated solution: no more solute dissolves at that temperature; solubility usually rises with temperature.
• Water is the universal solvent; a solution of a metal in a metal is an alloy.