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Q1Maths · Mensuration 2DSSC CGL 2025 · 21 Sep2025_Shift3 verified
A triangular field with base 40 m and height 30 m shares a side with a rectangle of length 40 m and breadth 25 m. Find the combined area and percentage of the triangle's area in the total.
40 मीटर आधार और 30 मीटर ऊंचाई वाला एक त्रिभुजाकार खेत 40 मीटर लंबाई और 25 मीटर चौड़ाई वाले एक आयत के साथ एक भुजा साझा करता है। कुल क्षेत्रफल और कुल में त्रिभुज के क्षेत्रफल का प्रतिशत ज्ञात कीजिए।
Answer: C) 1,600 m² and 37.5%1,600 मी² और 37.5%
Area of triangle = (1/2) × base × height = (1/2) × 40 × 30 = 600 m².
Area of rectangle = length × breadth = 40 × 25 = 1000 m².
Combined area = 600 + 1000 = 1600 m².
Percentage of triangle's area = (600/1600) × 100 = 37.5%.त्रिभुज का क्षेत्रफल = (1/2) × आधार × ऊँचाई = (1/2) × 40 × 30 = 600 m²।
आयत का क्षेत्रफल = लंबाई × चौड़ाई = 40 × 25 = 1000 m²।
संयुक्त क्षेत्रफल = 600 + 1000 = 1600 m²।
त्रिभुज के क्षेत्रफल का प्रतिशत = (600/1600) × 100 = 37.5%। -
Q2Maths · DiscountSSC CGL 2025 · 15 Sep2025_Shift2
A garment shop sells a shirt for ₹A, incurring a loss of 5%. During an end-of-season sale, they mark up the same shirt to ₹1.2A. At the sale, they provide a flat discount of 10% on this marked price. What will be the percentage profit or loss for the garment shop on that shirt during the sale?
एक गारमेंट की दुकान ₹A में एक कमीज बेचती है , जिससे 5% की हानि होती है । एक सीजन के अंत की सेल के दौरान , वे उसी कमीज का मूल्य ₹1.2A तक बढ़ा देते हैं । सेल में , वे इस अंकित मूल्य पर 10% की सीधी छूट देते हैं । सेल के दौरान उस कमीज पर गारमेंट की दुकान को कितने प्रतिशत लाभ या हानि होगी ?
Answer: C) 2.6% Profit2.6% लाभ
SP₁ = A at 5% loss ⇒ CP = A / 0.95.
New SP = 1.2A × 0.9 = 1.08A.
Profit = 1.08A − A/0.95 = 1.08A − 1.0526A = 0.0274A.
Profit % = (0.0274A) / (A/0.95) × 100 = 0.0274 × 95 ≈ 2.6 %.
Hence about 2.6% profit.विक्रय मूल्य (SP ₁ ) = A पर 5% हानि ⇒ क्रय मूल्य (CP) = A / 0.95.
नया विक्रय मूल्य (SP) = 1.2A × 0.9 = 1.08A.
लाभ = 1.08A − A/0.95 = 1.08A − 1.0526A = 0.0274A.
लाभ % = (0.0274A) / (A/0.95) × 100 = 0.0274 × 95 ≈ 2.6 %.
अतः लगभग 2.6% लाभ । -
Q3Maths · Mensuration 3DSSC Selection Post Ph-14 2026 · Graduate Level · 17 Sep 2026 · Q73
The ratio of the area of the base of a regular square pyramid to the area of one of its lateral faces is 2:1. Find the angle the lateral face makes with the base.
एक नियमित वर्गीय पिरामिड के आधार के क्षेत्रफल और उसके एक पार्श्व फलक के क्षेत्रफल का अनुपात 2:1 है। पार्श्व फलक द्वारा आधार के साथ बनाए गए कोण का मान ज्ञात कीजिए।
Answer: C) 60°60°
#IMG /home/claude/sp14/fig/G17/q073.png|6
Concept — the angle between a face and the base.
It is the angle θ at M (mid-point of a base edge) between the slant height PM and the line MO to the centre of the base.
cos θ = MO/PM = (a/2)/l
Step 1 — area of the base and of one face.
Base = a²
Lateral face (triangle) = 1/2 × a × l
Step 2 — use the ratio 2 : 1.
a² ÷ (1/2 × a × l) = 2
2a/l = 2
l = a
Step 3 — the angle.
cos θ = (a/2)/a = 1/2
θ = 60°
Answer: 60°
The slant height comes out equal to the base side — then cos θ = 1/2 at once.⟦TIMG1⟧
अवधारणा — फलक और आधार के बीच का कोण।
यह M (आधार के एक किनारे का मध्य-बिंदु) पर तिर्यक ऊँचाई (slant height) PM और आधार के केंद्र तक की रेखा MO के बीच का कोण θ है।
cos θ = MO/PM = (a/2)/l
चरण 1 — आधार और एक फलक का क्षेत्रफल।
आधार = a²
पार्श्व फलक (त्रिभुज) = 1/2 × a × l
चरण 2 — अनुपात 2 : 1 का प्रयोग करें।
a² ÷ (1/2 × a × l) = 2
2a/l = 2
l = a
चरण 3 — कोण।
cos θ = (a/2)/a = 1/2
θ = 60°
उत्तर: 60°
तिर्यक ऊँचाई आधार की भुजा के बराबर निकलती है — फिर तुरंत cos θ = 1/2। -
Q4Reasoning · SeriesSSC CGL 2025 Tier-I · 19 Sep_2025_Shift_1
Find out the WRONG number in the given series.
**336, 246, 166, 94, 36, -14**दी गई श्रृंखला में गलत संख्या ज्ञात कीजिए।
**336, 246, 166, 94, 36, -14**Answer: A) 9494
Differences should be -90, -80, -70, -60, -50 (decreasing by 10 each).
336, 246, 166, 96, 36, -14 — the correct fourth term is 96.
The series shows 94, so 94 is the WRONG term.अंतर -90, -80, -70, -60, -50 होने चाहिए (प्रत्येक 10 से घट रहा है)।
336, 246, 166, 96, 36, -14 — सही चौथा पद 96 है।
श्रृंखला में 94 दर्शाया गया है, अतः 94 गलत पद है। -
Q5Reasoning · Arithmetic ReasoningSSC Selection Post Ph-14 2026 · Matriculation - 21 Sep 2026 Shift 3
The difference between the present ages of X and Y is 8 years. Five years ago, the product of their ages was 84. What is the present age of the elder person?
Answer: B) 19 years
Rule: the difference between two ages never changes, so the ages five years ago also differ by 8.
Five years ago.
Let the younger be a; the elder is a + 8.
a × (a + 8) = 84
Two numbers 8 apart with product 84: 6 × 14 = 84
So the ages then were 6 and 14.
Present ages.
6 + 5 = 11
14 + 5 = 19
Answer: 19 years
Add the 5 years back — 14 is the trap for anyone who stops at the old age. -
Q6Reasoning · Calendar and ClockSSC Selection Post Ph-14 2026 · Matriculation - 25 Sep 2026 Shift 3
Between 12:00 and 1:00, when do the hour and minute hands form 120° for the first time?
Answer: B) 12:21 9/11
Rule: the minute hand gains 5.5° per minute on the hour hand, so time taken = gap to be created ÷ 5.5.
At 12:00.
Both hands at 12, gap = 0°
Gap needed.
120°
Time.
120 ÷ 5.5 = 120 × 2/11 = 240/11 = 21 9/11 minutes
Answer: 12:21 9/11
12:20 is the trap — the hour hand has moved 10° by then, so the gap is only 110°. -
Q7English · One Word SubstitutionSSC Selection Post Ph-12 2024 HSL · 25-Jun Shift 4 HSL
Select the option that can be used as a one-word substitute for the given group of words.
A person who renounces a religious or political belief or principle.Answer: C) Apostate
Here’s the explanation of the options:
• Apostate: This term specifically refers to a person who renounces or abandons their religious, political, or philosophical beliefs or principles. It fits the description perfectly.
• Ascetic: This refers to a person who leads a simple and self-disciplined life, often for religious or spiritual reasons. They may reject materialism, but not necessarily renounce their beliefs or principles.
• Atheist: An atheist is someone who does not believe in the existence of God or gods. While this involves a belief system, it doesn’t cover renouncing other types of beliefs or principles.
• Agnostic: An agnostic is someone who claims neither faith nor disbelief in the existence of God or a higher power, typically due to the belief that the truth is unknown or unknowable. This also doesn't fit the definition of renouncing beliefs.
So, apostate is the most appropriate term. -
Q8English · SynonymsSSC MTS 2024 · 22-Oct Shift 3
Select the most appropriate synonym of the given word.
IntractableAnswer: C) Defiant
Answer: Defiant
Explanation:
Intractable means difficult to manage, control, or deal with (जिसे संभालना मुश्किल हो, जिद्दी).
The best synonym is Defiant, which means openly resisting or disobedient (अवज्ञाकारी, विरोध करने वाला).
Other options:
• Compliant – willing to obey or agree (आज्ञाकारी, सहमत होने वाला) – opposite of intractable
• Versatile – able to do many things well (बहुपरकारी, बहुप्रतिभाशाली) – unrelated
• Proper – correct or appropriate (उचित) – unrelated
Only Defiant shares the same meaning as Intractable in the context of resistance or difficulty in control. -
Q9Current AffairsRBE current affairs · 27 October 2026
Researchers at IIT Bombay, led by Mahesh Tirumkudulu, developed a low-cost device in October 2026 to screen for anaemia and which other blood disorder using blood smear length?
आईआईटी बॉम्बे के शोधकर्ताओं ने, जिनका नेतृत्व महेश तिरुमकुदुलु ने किया, अक्टूबर 2026 में रक्त स्मीयर की लंबाई का उपयोग करके एनीमिया और किस अन्य रक्त विकार की जांच के लिए एक सस्ता उपकरण विकसित किया?
Answer: B) Sickle cell diseaseसिकल सेल रोग
IIT Bombay's Chemical Engineering department, led by Mahesh Tirumkudulu, developed a device to screen for anaemia and sickle cell disease using blood smear length, announced in October 2026. The technology is licensed to IIT Bombay startup Rheoheme Private Limited. It is being validated with NIRTH Jabalpur and AIIMS Nagpur.आईआईटी बॉम्बे के केमिकल इंजीनियरिंग विभाग ने, जिसका नेतृत्व महेश तिरुमकुदुलु ने किया, रक्त स्मीयर की लंबाई का उपयोग करके एनीमिया और सिकल सेल रोग की जांच के लिए एक उपकरण विकसित किया, जिसकी घोषणा अक्टूबर 2026 में की गई। यह तकनीक आईआईटी बॉम्बे के स्टार्टअप रियोहीम प्राइवेट लिमिटेड को लाइसेंस दी गई है। इसे एनआईआरटीएच जबलपुर और एम्स नागपुर के साथ सत्यापित किया जा रहा है। -
Q10Current AffairsRBE current affairs · 27 October 2026
In October 2026, the Defence Acquisition Council approved military purchases worth how much, including destroyers, K9 Vajra-T guns and drones?
अक्टूबर 2026 में, रक्षा अधिग्रहण परिषद ने विध्वंसक पोतों, के9 वज्र-टी तोपों और ड्रोनों सहित कितने मूल्य की सैन्य खरीद को मंजूरी दी?
Answer: C) Rs 2.12 lakh crore2.12 लाख करोड़ रुपये
The Defence Acquisition Council, chaired by Rajnath Singh, approved purchases worth Rs 2.12 lakh crore in October 2026. About 82% of the hardware will be sourced domestically. It included next-gen destroyers, K9 Vajra-T guns and kamikaze drones.रक्षा मंत्री राजनाथ सिंह की अध्यक्षता वाली रक्षा अधिग्रहण परिषद ने अक्टूबर 2026 में 2.12 लाख करोड़ रुपये की खरीद को मंजूरी दी। लगभग 82% हार्डवेयर स्वदेशी रूप से प्राप्त किया जाएगा। इसमें अगली पीढ़ी के विध्वंसक पोत, के9 वज्र-टी तोपें और कामीकाज़े ड्रोन शामिल थे।
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