RRB Technician Grade III 2024-25 – 28 December 2024 Shift 3 · Numericals on force and momentum
Q101. Find the magnitude of applied force on a box of mass 10 kg for 20 s. It increases the box's velocity from 5 m s⁻¹ to 15 m s⁻¹ .
- (a) 5 N
- (b) 10 N
- (c) 1 N
- (d) 4 N
Answer & solution
Answer: (a) 5 N
Correct Answer: Option 1 — 5 N
📖 Given
• Mass of the box, m = 10 kg
• Initial velocity, u = 5 m s⁻¹
• Final velocity, v = 15 m s⁻¹
• Time for which the force acts, t = 20 s
✍️ Formula
a = (v − u) / t and F = ma
🔢 Solution
• a = (15 − 5) / 20
• a = 10 / 20 = 0.5 m s⁻²
• F = m × a = 10 × 0.5
• F = 5 N
So a steady force of 5 newton is enough to speed the box up by 10 m s⁻¹ over 20 seconds. The same answer follows from the momentum form: F = (mv − mu)/t = (150 − 50)/20 = 5 N.
❌ Why the other options are incorrect
✗ 10 N — this is obtained by using the change in velocity (10) directly as the acceleration, forgetting to divide by the time of 20 s.
✗ 1 N — this comes from wrongly dividing again by the mass or from taking a = 0.1 m s⁻²; the correct acceleration is 0.5 m s⁻².
✗ 4 N — this comes from a slip such as using u = 7 m s⁻¹ or a wrong subtraction; the correct velocity change is 15 − 5 = 10 m s⁻¹.
📌 SSC & Railway Exam Facts
• Newton's Second Law: F = ma = (mv − mu)/t; 1 N = 1 kg m s⁻².
• Impulse = F × t = change in momentum; SI unit N s, same as kg m/s.
• Equations of motion: v = u + at, s = ut + ½at², v² = u² + 2as.
• If the force acts opposite to the motion, the acceleration is negative (retardation).
• Momentum is conserved in the absence of an external unbalanced force.
📖 Given
• Mass of the box, m = 10 kg
• Initial velocity, u = 5 m s⁻¹
• Final velocity, v = 15 m s⁻¹
• Time for which the force acts, t = 20 s
✍️ Formula
a = (v − u) / t and F = ma
🔢 Solution
• a = (15 − 5) / 20
• a = 10 / 20 = 0.5 m s⁻²
• F = m × a = 10 × 0.5
• F = 5 N
So a steady force of 5 newton is enough to speed the box up by 10 m s⁻¹ over 20 seconds. The same answer follows from the momentum form: F = (mv − mu)/t = (150 − 50)/20 = 5 N.
❌ Why the other options are incorrect
✗ 10 N — this is obtained by using the change in velocity (10) directly as the acceleration, forgetting to divide by the time of 20 s.
✗ 1 N — this comes from wrongly dividing again by the mass or from taking a = 0.1 m s⁻²; the correct acceleration is 0.5 m s⁻².
✗ 4 N — this comes from a slip such as using u = 7 m s⁻¹ or a wrong subtraction; the correct velocity change is 15 − 5 = 10 m s⁻¹.
📌 SSC & Railway Exam Facts
• Newton's Second Law: F = ma = (mv − mu)/t; 1 N = 1 kg m s⁻².
• Impulse = F × t = change in momentum; SI unit N s, same as kg m/s.
• Equations of motion: v = u + at, s = ut + ½at², v² = u² + 2as.
• If the force acts opposite to the motion, the acceleration is negative (retardation).
• Momentum is conserved in the absence of an external unbalanced force.