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Light - Refraction and Lenses PYQs – Physics, SSC & Railway

103 Light - Refraction and Lenses (Physics) questions asked in recent SSC and Railway exams, newest first, with exam, date & shift, answers and solutions – page 2 of 2.

📚 103 questionsSSC 3 · Railway 100
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RRB JE CBT-1 2024-25 – 17 December 2024 Shift 2 · Numericals on refraction and lenses

Q101. If the refractive index of water is 1.33, then the speed of light in water is approximately ___________.

  1. (a) 1.5×10⁸ m/s
  2. (b) 2.26×10⁸ m/s
  3. (c) 4×10⁸ m/s
  4. (d) 3×10⁸ m/s
Answer & solution

Answer: (b) 2.26×10⁸ m/s

Formula — refractive index.
Refractive index = speed of light in vacuum ÷ speed of light in the medium
n = c ÷ v ⇒ v = c ÷ n
Substitute.
c = 3 × 10^(8) m/s, n = 1.33
v = 3 × 10^(8) ÷ 1.33
= 2.26 × 10^(8) m/s
Answer: 2.26 × 10^(8) m/s
Revision note — Refractive index and speed of light
• Light is fastest in vacuum (3 × 10^(8) m/s); every medium has n > 1.
• Speeds: water (n = 1.33) about 2.25 × 10^(8) m/s; glass (n = 1.5) 2 × 10^(8) m/s; diamond (n = 2.42) about 1.24 × 10^(8) m/s.
• Higher n ⇒ optically denser ⇒ slower light.
• On refraction the speed and wavelength change, but the frequency stays the same.
Any answer above 3 × 10^(8) m/s is impossible — light can never travel faster in water than in vacuum.
Also asked from this topic: the speed of light in glass of refractive index 1.5 (2 × 10^(8) m/s); the property of light that does not change on refraction (frequency).
RRB JE CBT-1 2024-25 – 16 December 2024 Shift 3 · Convex lens - image formation and uses

Q102. In the case of a thin lens, how are the centres of curvature typically positioned relative to the optical centre?

  1. (a) They are closer to the edge than to the optical centre.
  2. (b) They coincide with the optical centre.
  3. (c) They are equidistant from the optical centre.
  4. (d) They are located on the lens surface itself.
Answer & solution

Answer: (c) They are equidistant from the optical centre.

Answer: Option 3 — They are equidistant from the optical centre.
A thin lens with equally curved faces has its two centres of curvature, C_(1) and C_(2), on the principal axis, one on each side, at the same distance from the optical centre O.
Revision note — Spherical lens terms
• Centre of curvature (C): centre of the sphere of which a lens surface is a part; a lens has two (C_(1), C_(2)).
• Optical centre (O): the central point of the lens; a ray through it passes undeviated.
• Principal axis: the line through both centres of curvature and O.
• Principal focus (F): a lens has two foci, F_(1) and F_(2); the distance OF is the focal length f.
• For a thin lens, the points at 2F_(1) and 2F_(2) are used as the centres of curvature in ray diagrams (radius R = 2f).
• All lens distances are measured from the optical centre.
Do not mix these up
• Lens vs mirror — a mirror has one centre of curvature and one focus; a lens has two of each.
Also asked from this topic: the path of a ray through the optical centre of a thin lens (continues without deviation); the point from which lens distances are measured (the optical centre).
RRB JE CBT-1 2024-25 – 16 December 2024 Shift 3 · Convex lens - image formation and uses

Q103. In which case will a lens produce a magnification of exactly 1?

  1. (a) When the object is placed at the focal point
  2. (b) When the object is at infinity
  3. (c) When the object is placed at twice the focal length
  4. (d) When the object is placed between centre of curvature and focal point
Answer & solution

Answer: (c) When the object is placed at twice the focal length

Answer: Option 3 — When the object is placed at twice the focal length
For a convex lens, an object at 2F₁ gives an image at 2F₂.
The image is real, inverted and of the same size — magnification m = −1, i.e. size ratio exactly 1.
Revision note — Image formation by a convex lens
• Object at infinity → image at F₂, highly diminished, real, inverted.
• Object beyond 2F₁ → image between F₂ and 2F₂, diminished, real, inverted.
• Object at 2F₁ → image at 2F₂, same size, real, inverted.
• Object between F₁ and 2F₁ → image beyond 2F₂, enlarged, real, inverted.
• Object at F₁ → image at infinity, highly enlarged.
• Object between F₁ and O → image on the same side, virtual, erect, enlarged — the magnifying glass.
• Magnification m = v/u = h′/h; a negative m means real and inverted, positive means virtual and erect.
Do not mix these up
• m = −1 vs m = +1 — −1 is a real, inverted, same-size image (object at 2F); +1 is what a plane mirror gives (virtual, erect, same size).
Also asked from this topic: where the image forms when the object is at 2F₁ of a convex lens (at 2F₂); where to place the object for a real image twice its size (between F and 2F).
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