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Q1Maths · Profit & LossSSC CGL 2025 Tier I
A wholesaler purchases 200 wireless headphones at a cost of ₹300 each. He intends to set a selling price such that selling only 150 units would still give him a 50% profit on the total investment. Due to a music festival in the city, he ends up selling 170 units. Assume the remaining units cannot be sold and have zero salvage value. What is the wholesaler’s actual profit percentage on the total investment?
एक थोक विक्रेता 200 वायरलेस हेडफ़ोन ₹300 प्रति हेडफ़ोन की दर से खरीदता है। उसका विक्रय मूल्य ऐसा निर्धारित करने का इरादा है कि केवल 150 यूनिट बेचने पर भी उसे कुल निवेश पर 50% लाभ प्राप्त हो। शहर में एक संगीत समारोह होने के कारण, वह केवल 170 यूनिट ही बेच पाता है। मान लीजिए कि शेष यूनिट बेची नहीं जा सकीं और उनका अवशिष्ट मूल्य शून्य है। कुल निवेश पर थोक विक्रेता का वास्तविक लाभ प्रतिशत क्या है?
Answer: B) 70%
Solution:
CP = 200 × 300 = C
SP per unit = (C × 150%)/150
Actual SP for 170 units:
= [(C × 150%)/150]× 170
Profit% = 150% × 170/150 ⇒ 170%
So, Actual Profit% = 170% - 100% ⇒ 70% -
Q2Maths · SimplificationSSC CHSL 2025 · SSC_CHSL_25Nov2025_Shift2_Maths.VERIFIED
A man bought 4(3/5) kg of rice and used 2(7/8) kg for cooking. He sold the remaining rice equally in 3 bags. How much rice did he put in each bag?
एक व्यक्ति ने 4(3/5) किग्रा चावल खरीदा और उसमें से 2(7/8) किग्रा खाना बनाने के लिए इस्तेमाल किया। उसने शेष चावल को 3 बोरियों में समान रूप से बेच दिया। उसने प्रत्येक बोरी में कितना चावल डाला?
Answer: C) 23/40 kg23/40 किग्रा
Bought = 4(3/5) = 23/5 kg.
Used = 2(7/8) = 23/8 kg.
Remaining = 23/5 − 23/8 = (184 − 115)/40 = 69/40 kg.
Each bag = 69/40 ÷ 3 = 69/120 = 23/40 kg.खरीदा गया = 4(3/5) = 23/5 किग्रा।
इस्तेमाल किया गया = 2(7/8) = 23/8 किग्रा।
शेष = 23/5 − 23/8 = (184 − 115)/40 = 69/40 किग्रा।
प्रत्येक बोरी में = 69/40 ÷ 3 = 69/120 = 23/40 किग्रा। -
Q3Maths · GeometrySSC CHSL 2025 · SSC_CHSL_20Nov2025_Shift3_Maths.VERIFIED
In a circle, there are two parallel chords of lengths 10 cm and 24 cm.
Both chords are on the same side of the center . The distance between them is 7 cm. Find the area of the circle.एक वृत्त में, 10 सेमी और 24 सेमी लंबाई की दो समानांतर जीवाएं हैं।
दोनों जीवाएं केंद्र के एक ही ओर हैं। उनके बीच की दूरी 7 सेमी है। वृत्त का क्षेत्रफल ज्ञात करें।Answer: A) 169π square cm169π वर्ग सेमी
Let d1 = distance of chord (24 cm) from center , d2 = distance of chord (10 cm) from center .
d1² + 12² = r² and d2² + 5² = r²
Same side: d2 = d1 + 7
(d1 + 7)² + 25 = d1² + 144
14d1 + 49 + 25 = 144 → 14d1 = 70 → d1 = 5
r² = 25 + 144 = 169
Area = πr² = 169π sq cmमाना d1 = केंद्र से जीवा (24 सेमी) की दूरी, d2 = केंद्र से जीवा (10 सेमी) की दूरी।
d1² + 12² = r² और d2² + 5² = r²
एक ही तरफ: d2 = d1 + 7
(d1 + 7)² + 25 = d1² + 144
14d1 + 49 + 25 = 144 → 14d1 = 70 → d1 = 5
r² = 25 + 144 = 169
क्षेत्रफल = πr² = 169π वर्ग सेमी -
Q4Reasoning · SyllogismSSC Selection Post Ph-14 2026 · Higher Secondary - 26 Sep 2026 Shift 1
Statements:
1. All flowers are plants.
2. Some plants are trees.
Conclusions:
I. Some trees are flowers.
II. All flowers are trees.Answer: D) Neither I nor II follows
Rule: take the statements as true and test each conclusion against every arrangement they allow; a conclusion follows only if it holds in all of them.
What the statements fix:
• flowers lie entirely inside plants.
• plants and trees share some members.
• Nothing is said about flowers and trees directly.
Conclusion I — "Some trees are flowers" does not follow.
The plants that are trees may lie outside the flowers circle.
All + Some gives no conclusion between the outer classes.
Of the 20 arrangements the statements allow, 4 have no tree that is a flower, so "some" is not definite.
Conclusion II — "All flowers are trees" does not follow.
It would need every flower inside the trees circle.
Only 8 of the 20 arrangements put them there — the statements do not force it.
#IMG /home/claude/sp14/fig/H26/q010.png|7
So neither conclusion follows.
Answer: Neither I nor II follows
All + Some = no definite link — the "some" may sit on the part of plants that holds no flowers. -
Q5Reasoning · Mathematical OperationsSSC CPO 2025 Paper-I · CPO 11 Dec 2025 Shift 1
**Data Entry Operator (Contractual) —**
**Eligibility Criteria (as on 01-04-2025):**
1. Minimum 18 years old.
2.Should have passed Secondary Examination (10+2) with any subject.
3. Should have appeared for at least 40 words per minute (wpm) typing test.
4. Must commit to a minimum 1-year contract.
**Case:**Mark is 20 years old and has a B.Sc. in Physics. His typing speed is 30 wpm, and he states he will work only for 8 months.
**Question:**What decision should be made om vivek’s case?**डाटा एंट्री ऑपरेटर (संविदात्मक) —**
**पात्रता मापदंड (01-04-2025 तक):**
1. न्यूनतम 18 वर्ष की आयु।
2. किसी भी विषय के साथ माध्यमिक परीक्षा (10+2) उत्तीर्ण की हो।
3. कम से कम 40 शब्द प्रति मिनट (wpm) टाइपिंग टेस्ट में उपस्थित हुआ हो।
4. न्यूनतम 1 वर्ष के अनुबंध के लिए प्रतिबद्ध होना चाहिए।
**मामला:**मार्क 20 वर्ष का है और उसके पास भौतिकी में B.Sc. की डिग्री है। उसकी टाइपिंग गति 30 wpm है, और वह कहता है कि वह केवल 8 महीने के लिए काम करेगा।
**प्रश्न:**विवेक के मामले में क्या निर्णय लिया जाना चाहिए?Answer: C) Select the candidate provisionallyउम्मीदवार का अनंतिम चयन करें
Mark fails intwo conditions:
His typing speed is only30 wpm, while the requirement is40 wpm.
He is ready to work for only8 months, while the minimum contract requirement is1 year.
Answer: Reject the applicationमार्कदो स्थितियोंमें विफल है:
उसकी टाइपिंग गति केवल30 wpmहै, जबकि आवश्यकता40 wpmहै।
वह केवल8 महीनेके लिए काम करने को तैयार है, जबकि न्यूनतम अनुबंध की आवश्यकता1 वर्षहै।
उत्तर: आवेदन खारिज करें -
Q6Reasoning · Dictionary OrderSSC Selection Post Ph-14 2026 · Matriculation - 16 Sep 2026 Shift 3
Select the option that correctly completes the following series.
Atom, Molecule, Cell, ?Answer: B) Tissue
Rule: a word series climbs or falls one level at a time — name the order before choosing.
The order of organisation (small to large).
Atom → Molecule → Cell → Tissue → Organ → Organ system → Organism
Next level.
Cells of one kind group together to form a tissue.
Answer: Tissue
Electron and proton are smaller than an atom, and a compound is a chemical level below the cell — all three go backwards. -
Q7English · Sentence ImprovementSSC MTS 2024 · 11-Nov Shift 3
Select the most appropriate option that can substitute the underlined words in the given sentence.
I have never had and never will be dependent on him.Answer: D) never been
Answer: b) has never been
Explanation:
The correct form for the present perfect tense with "I" is "have never been", but since the subject is "I," the option closest and correct here is "has never been" if referring to a singular third person, but since the sentence is about "I," none of the options perfectly match "have never been."
However, among given options, "has never been" fits best in formal correction context because:
• "was never being" is incorrect tense and form
• "never has" is incomplete
• "never been" is incomplete without auxiliary verb
But the sentence should ideally be:
"I have never been and never will be dependent on him."
Since that exact option is missing, the best substitute given is "has never been" for correct grammatical form in similar sentences.
If you want, I can rephrase the sentence fully correctly! -
Q8English · AntonymsSSC Steno 2026 T-1 · 09-Sep-2026 Shift 2
What is the antonym of "Irascible"?
Answer: B) Tranquil
Meaning: irascible = quick to anger, hot-tempered (चिड़चिड़ा, क्रोधी स्वभाव का).
tranquil = calm, peaceful, undisturbed (शांत, स्थिर) — the opposite temperament, so option 2.
A tranquil person does not flare up; an irascible one flares up at nothing.
Why the others are wrong.
• petulant = childishly sulky and bad-tempered (झुँझलाया हुआ, रूठा हुआ) — a near synonym, not an opposite.
• hostile = unfriendly, showing open enmity (शत्रुतापूर्ण, विरोधी) — also on the angry side of the scale.
• fractious = irritable and ready to quarrel (झगड़ालू, चिड़चिड़ा) — very close indeed to irascible.
Latin ira means anger — irascible, irate and ire all grow from that one root. -
Q9Current AffairsRBE current affairs · 29 October 2026
The Union Cabinet approved the Container Manufacturing Promotion Scheme (CMPS) in October 2026 with an outlay of how much, to boost India's container manufacturing capacity?
केंद्रीय मंत्रिमंडल ने अक्टूबर 2026 में भारत की कंटेनर निर्माण क्षमता बढ़ाने के लिए कंटेनर मैन्युफैक्चरिंग प्रमोशन स्कीम (CMPS) को कितने परिव्यय के साथ मंजूरी दी?
Answer: C) Rs 10,000 crore10,000 करोड़ रुपये
The Cabinet approved the Rs 10,000 crore Container Manufacturing Promotion Scheme in October 2026. It aims to raise India's annual container manufacturing capacity from about 70,000 TEU to 7.5 lakh TEU. The scheme runs from FY 2027-28 to FY 2039-40 under the Ministry of Ports, Shipping and Waterways led by Sarbananda Sonowal.मंत्रिमंडल ने अक्टूबर 2026 में 10,000 करोड़ रुपये की कंटेनर मैन्युफैक्चरिंग प्रमोशन स्कीम को मंजूरी दी। इसका उद्देश्य भारत की वार्षिक कंटेनर निर्माण क्षमता को लगभग 70,000 TEU से बढ़ाकर 7.5 लाख TEU करना है। यह योजना वित्त वर्ष 2027-28 से वित्त वर्ष 2039-40 तक सर्बानंद सोनोवाल के नेतृत्व वाले पत्तन, पोत परिवहन और जलमार्ग मंत्रालय के अंतर्गत चलेगी। -
Q10Current AffairsRBE current affairs · 29 October 2026
The National Pharmaceutical Pricing Authority (NPPA) revised the MRP of 543 branded anti-cancer drugs, effective from which date in November 2026?
राष्ट्रीय औषधि मूल्य निर्धारण प्राधिकरण (NPPA) ने 543 ब्रांडेड कैंसर-रोधी दवाओं के MRP में संशोधन किया, जो नवंबर 2026 में किस तारीख से प्रभावी हुआ?
Answer: D) 9 November 20269 नवंबर 2026
NPPA's revised MRPs for 543 anti-cancer drug brands became effective from 9 November 2026. NPPA functions under the Department of Pharmaceuticals, Ministry of Chemicals and Fertilizers. The move followed NPPA's October 2026 trade margin rationalisation of 137 non-scheduled anti-cancer drugs.NPPA द्वारा 543 कैंसर-रोधी दवा ब्रांडों के संशोधित MRP 9 नवंबर 2026 से प्रभावी हुए। NPPA रसायन और उर्वरक मंत्रालय के औषध विभाग के अंतर्गत कार्य करता है। यह कदम NPPA द्वारा अक्टूबर 2026 में 137 गैर-अनुसूचित कैंसर-रोधी दवाओं के व्यापार मार्जिन युक्तिकरण के बाद उठाया गया।
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